An example : (2+3j)(3+2j)=13j. So the real part of the product (2+3j)(3+2j) is zero, but (2+3j) is not equal to zero, nor (3+2j). So At 11:15 , the reason of why the some of phasors is equal to zero deserves a better explanation. Regardless of that, it is a good video; thank you very much !

A phasor is a vector in the complex plane with a magnitude of Vo and an angle φ. The Re(Vo) is a different vector on the real axis with a different magnitude. So your final equation is correct. But the actual KVL must be Vo+V1+V2+V3=0

## 8 Comments

## Ethan Nicolielo

first

## Jam

I feel as though you could've cut off at least a minute of the video by writing "Sigma(V_i…)" instead of each term directly.

Just creative criticism. Good video regardless.

## asiel smith

Second

## asiel smith

Church hopes law

## lumpi806

An example : (2+3j)(3+2j)=13j. So the real part of the product (2+3j)(3+2j) is zero, but (2+3j) is not equal to zero, nor (3+2j). So At 11:15 , the reason of why the some of phasors is equal to zero deserves a better explanation. Regardless of that, it is a good video; thank you very much !

## Nothingness

thr voltage signs of v1 v2 are opposite, as voltage drops, so – should be at the end,

the equaltion should be Vo-v1-V2-V3

## Nothingness

why wasn't imaginary part taken zero?

## Dimitris Gkontoras

A phasor is a vector in the complex plane with a magnitude of Vo and an angle φ. The Re(Vo) is a different vector on the real axis with a different magnitude. So your final equation is correct. But the actual KVL must be Vo+V1+V2+V3=0